posted by Stephanie .
What is the freezing point of a solution of 12.0 g of CCl4 dissolved in 750.0 g of benzene? The freezing point of benzene is 5.48°C; Kf is 5.12°C/m.
delta T = i*Kb*molality.
molality = moles/kg
mols = grams/molar mass.
Use equation 3 to convert grams CCl4 to moles.
Use equation 2 to convert moles to molality.
Use equation 1 to determine delta T (i = 1).
Then delta T = T(normal)-T(solution). Calcualte T of the solution.
Post your work if you get stuck.