How would SiO4 Lewis structure look like?
Each oxygen has 1 unfilled electron, so would there be 2 double bonds?
Thanks in advance.
Ah, my bad, its SO4 2-
I wonder if you mean SiO2? Is there an SiO4? There is a silicate ion, SiO4^-2
Actually, silicate is SiO3^-2. And it would have 1 Si=O double bond. The other Si-O bonds are single bonds.
I got the element wrong :S
The element is actually sulphur and not silicon.
So sulphur has 6 valence electrons, wouldnt that only fit 2 atoms of oxygen?
do you know the rules?
1. 4 + 6(4) = 28 valence electrons
2. 8(5) = 40 electrons wanted
3. 40 - 28 = 12 shared electrons
4. 12 / 2 = 6 bonds
5. 28 - 12 = 16 electrons not in bonds
6. 16 / 2 = 8 lone pairs
create the structure from this
and yes 6 bonds means 2 double bonds are formed
and try answering mine please =)
**
:O:
** . **
:O :S:O:
** . **
:O:
**
?
hope this structure is understandable
what is the -2 relevant to?