# algebra

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Jack usually mows his lawn in 6 hours. Marilyn can mow the same lawn in 5 hours How much time would it take them to mow the lawn together?

• algebra -

In 30 hours, Jack mows 5 lawns, and Marilyn can mow 6 lawns.

That is 11 lawns in 30 hours.

rate=11/30 lawns/hr.

so one lawn will take 30/11 hrs.

• algebra -

Jack's rate = job/6
Marilyn's rate = job/5

their combined rate = job/6 + job/5
= 11job/30

job = rate x time

so time for combined effort = job/rate
= job/(11job/30)
= 30/11
So it takes 30/11 hours
= 2 8/11 hours

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