Math
posted by Jon .
Write the standard form of the equation of the circle that passes through (0,4) and has its center at (3,1).
(xh)^2 + (yk)^2 = r^2
(x+3)^2 + (y+1)^2 = r^2
r^2 = d
d = sqrt(x2x1)^2 +(y2y1)^2
d = sqrt(30)^2 + (14)^2
d = 3^2 + 5^2
d = sqrt34
(x+3)^2 + (y+1)^2 = r^2
(x+3)^2 + (y+1)^2 = sqrt34 <(answer)
I got half off, she just circled the sqrt34 part

for a circle with centre (h,k) and radius r
the standard form is
(xh)^2 + (yk)^2 = r^2
your right side should have been 34 not √34
BTW, an easier and quicker way would be to start with
(x+3)^2 + (y+1)^2 = r^2 , now sub in (0,4)
9 + 25 = d^2 = 34
put that back in, done!
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