A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length.
a)Find Mechanical Advantage:
M.A.=Load/Effort
M.A.=8000/159.155
M.A.=50.265 (ans.)
b)Find the velocity ratio:
Efficiency=M.A./V.R.
V.R.=M.A./eff.
V.R.=50.265/0.4
V.R.=125.66 (ans.)
c)Find the mean pitch of thread:
V.R.=distance moved by effort/dist. moved by load
V.R.=2piL/2*pitch of thread
2*pitch of thread=2pi*200mm/125.66
Pitch of thread=10/2
Pitch of thread=5mm (ans.)
To find the Mechanical Advantage (M.A.), you need to divide the load by the effort. In this case, the load is given as 8kN (kilonewtons) and the effort is 159.155N.
So M.A. = Load / Effort
M.A. = 8000N / 159.155N
M.A. = 50.265
Therefore, the Mechanical Advantage is 50.265.
To find the velocity ratio (V.R.), you need to divide the Mechanical Advantage by the efficiency. The efficiency is given as 40%.
So V.R. = M.A. / Efficiency
V.R. = 50.265 / 0.4
V.R. = 125.66
Therefore, the velocity ratio is 125.66.
To find the mean pitch of the thread, you can use the velocity ratio formula:
V.R. = Distance moved by effort / Distance moved by load
In this case, the distance moved by effort is the circumference of a circle with a radius of 20cm (lever length) given as 2πL (2 * π * 20cm). The distance moved by the load is the pitch of the thread times 2 (since each revolution moves the load by the pitch twice).
So 2 * pitch of thread = (2πL) / V.R.
2 * pitch of thread = (2π * 20cm) / 125.66
2 * pitch of thread = (40π) / 125.66
pitch of thread = (40π) / (2 * 125.66)
pitch of thread = 10 / 2
Therefore, the mean pitch of the thread is 5mm.