1. Hydrogen bromide(HBr) is a strong, highly corrosive acid and what is the pOH of a 0.0375M HBr solution?

a)12.57
b)12.27
c)1.73
d)1.43
I can't fogure out what the answer should be as I don't know whether 0.0375M is the [H^+] or [OH^-]
If 0.0375M is the [OH^-], then I know the answer is 1.43(d). But if 0.0375M is [H^+] ,it would be12.57(a), right?

2. Which of the following is NOT a characteristic of a base?
a)bitter taste
b)ability to conduct electricity
c) reactivity with some metals
d)slippery feel
I guess it is b,is it right?

Thanks in advance.

yes you are correct for both questions

if it is not stated that it is [H+] or [OH-] then you should ask your teacher

In the case of HBr, you know the ionization is

HBr ==> H^+ + Br^-
So the 0.0375 is the (H^+) which makes the pH = 1.43 and the pOH = 12.57.

For the second question, I think the answer is "None of the above."
a,c, and d DEFINITELY are true. b is true, also, if we are talking about a solution. The solid base won't conduct electricity. Perhaps b is the best choice but I think it's a poor question (actually poor answers).

lasfh;ja

1. Well, I hate to say you're in a bit of a pickle with this one! But fear not, Clown Bot is here to help you out. In this case, since hydrogen bromide (HBr) is a strong acid, you can assume that 0.0375M represents the concentration of [H+]. So, you're right on the money with your answer of 12.57, option (a). Great job!

2. Ah, the good ol' NOT question! Sneaky, aren't they? You are absolutely correct once again, my friend. Option (b), the ability to conduct electricity, is not a characteristic of a base. While bases can conduct electricity when dissolved in water (due to the presence of ions), it is actually metals that excel at conducting the electric symphony. So, kudos to you for picking the right option!

Keep up the great work! If you have any more questions, feel free to ask.

To determine the pOH of a Hydrogen bromide(HBr) solution, you need to know the concentration of either [OH^-] or [H^+]. In this case, the concentration given is 0.0375M, but it is not specified whether it is the concentration of [OH^-] or [H^+].

If 0.0375M is the concentration of [OH^-], you can use the equation pOH = -log[OH^-]. Plugging in the value, you would calculate pOH = -log(0.0375) = 1.43. Therefore, option (d) would be the correct answer.

If 0.0375M is the concentration of [H^+], you can use the fact that in water, [H^+] [OH^-] = 1x10^-14 at 25°C. Knowing [H^+], you can calculate [OH^-] as follows: [OH^-] = 1x10^-14 / [H^+]. Plugging in the value, you would calculate [OH^-] = 1x10^-14 / 0.0375 = 2.67x10^-13 M. Then, you can use the equation pOH = -log[OH^-] and calculate pOH = -log(2.67x10^-13) = 12.57. In this case, option (a) would be the correct answer.

Without further information, it is not possible to definitively determine whether 0.0375M is the concentration of [OH^-] or [H^+], so both answer choices (a) and (d) are possibilities.

For the second question, you are correct. Conducting electricity is not a characteristic of a base. Therefore, option (b) would be the correct answer.

pOH is -log[OH-] so the answer would be 1.43