a volumetric pyrex glass is calibrated at 20C. It is filled to the 100ml mark with 35C acetone. What is the volume of the acetone when it is cooled to 20C(b=1.5x10^-4C-1)

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To calculate the final volume of the acetone when it is cooled to 20°C, we can use the principle of thermal expansion. The formula for calculating the change in volume due to temperature change is given by:

ΔV = V * β * ΔT

Where:
ΔV = Change in volume
V = Initial volume
β = Coefficient of thermal expansion
ΔT = Change in temperature

In this case, we know:
V = 100 mL = 100 cm^3 (since 1 mL is equivalent to 1 cm^3)
β = 1.5 × 10^-4 °C^-1 (given)
ΔT = 35°C - 20°C = 15°C (since the acetone is cooled from 35°C to 20°C)

Plugging in these values, we can calculate the change in volume:

ΔV = 100 cm^3 * (1.5 × 10^-4 °C^-1) * 15°C

ΔV = 0.225 cm^3

To obtain the final volume, subtract the change in volume from the initial volume:

Final volume = Initial volume - Change in volume
Final volume = 100 cm^3 - 0.225 cm^3
Final volume = 99.775 cm^3

Therefore, the volume of the acetone when it is cooled to 20°C is approximately 99.775 cm^3.