Applied Mech. (with my answer..lol)
posted by Henri .
What load can be lifted by a screw jack given:
Toggle1 length:520mm
Force applied:230N
Toggle2 lenght:445mm
Force applied:300.557N
Mean pitch of thread:13mm
S.J. efficiency:35%
My answer:
Assuming T2 to be 520mm long, the equivalent force would be:
0.445mX300.557N=0.52m X F2
F2=133.748/0.52
F2=257.2N
Assuming T1 as lifting the entire load:
Velocity Ratio of SJ=Circ of leverage/pitch of thread
V.R.=2pi0.52/0.013
V.R.=251.3
then:
Efficiency=Mech. adantage/V.R.
M.A.=251.3X0.35
M.A.=87.955
The load lifted by the Jack is:
M.A.=Load/effort
Load lifted=M.A.*(F1+F2)
Load=87.955*(230+257.2)
Load=42851.8/9.81
Load=4372.62kg/1000
Load=4.373tonnes
Respond to this Question
Similar Questions

Velocity Ratio
Does my work make sense? A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length. a) Find the mechanical advantage. Mechanical 
Please check my math
A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length. a) Find the mechanical advantage. Mechanical Advantage=Load/Effort … 
physic
A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length. a) Find the mechanical advantage. b) Find the velocity ratio. c) … 
Is my math correct(2)
What load can be lifted by a screw jack given: Toggle1 length:520mm Force applied:230N Toggle2 lenght:445mm Force applied:300.557N Mean pitch of thread:13mm S.J. efficiency:35% My answer: Assuming T2 to be 520mm long, the equivalent … 
Physics
A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length. a)Find Mechanical Advantage: M.A.=Load/Effort M.A.=8000/159.155 M.A.=50.265 … 
Physics
A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length. a)Find Mechanical Advantage: M.A.=Load/Effort M.A.=8000/159.155 M.A.=50.265 … 
Physics (is this right?)
A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length. a)Find Mechanical Advantage: M.A.=Load/Effort M.A.=8000/159.155 M.A.=50.265 … 
Please check my math
A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length. a)Find Mechanical Advantage: M.A.=Load/Effort M.A.=8000/159.155 M.A.=50.265 … 
science
A force of 625 N is applied to a hydraulic jack piston that is 0.04 m in diameter. If the piston which supports the load has a diameter of 0.60 m, how much mass can be lifted by the jack? 
Science/Biomaterials
Given the following properties, how much stretch would you expect to occur in a specimen of polyethylene to which a tensile load is applied?