the specific heat capacity of mercury is 0.033 cal/(g))degrees Celsius)How many grams of Hg could be raised to 50 degrees celsius from 27 degrees celsius with 381 joules?
Mass Hg x specific heat Hg x delta T = 381
Solve for mass Hg.
To solve this problem, we need to use the formula:
q = mcΔT
Where q is the amount of heat energy transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
Given:
Specific heat capacity of mercury (c) = 0.033 cal/(g·°C)
Initial temperature (T₁) = 27 °C
Final temperature (T₂) = 50 °C
Heat energy transferred (q) = 381 joules
First, we need to convert the heat energy transferred from joules to calories since the specific heat capacity is given in calories.
To convert joules to calories, we use the conversion factor: 1 calorie = 4.184 joules.
So, 381 joules = 381/4.184 calories = 91.19 calories.
Now we can apply the formula:
q = mcΔT
ΔT = T₂ - T₁ = 50 °C - 27 °C = 23 °C
We can rearrange the formula to solve for the mass (m):
m = q / (c * ΔT)
Substituting the given values:
m = 91.19 calories / (0.033 cal/(g·°C) * 23 °C)
m = 91.19 calories / (0.759 cal/g)
m ≈ 120.15 grams
Therefore, approximately 120.15 grams of mercury could be raised from 27 °C to 50 °C with 381 joules of heat energy.