Advanced Math
posted by Anonymous .
Find the principle root (64)1/6. Express the result in the form a+bi.
(2i)^6= 64 = (64)1/6= 0+2i
I got it wrong, please help.

you have 64@180 on the complex plane.
the sixth root of that is ..
2@30
in rectangular coordinates...
2cos30+2isin30
Try that. 
Ok but are you sure it's ok for how they want me to express it?
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