How much water mest be added to 6 ounces of a 20% acid solution to obtain a 15% acid solution?
To find out how much water needs to be added to a 6-ounce, 20% acid solution to obtain a 15% acid solution, we can use a basic calculation using the concept of dilution. The amount of acid in the final solution will be the same, so let's set up an equation:
Let x represent the amount of water (in ounces) to be added.
Since the initial solution is 20% acid, we have:
6 ounces * 0.20 (20%) = 1.2 ounces of acid
In the final solution, we want 15% acid and the total volume is 6 + x ounces. The amount of acid in the final solution remains the same, so we can set up the equation:
1.2 ounces = (6 + x) * 0.15 (15%)
Now, let's solve the equation for x:
1.2 = 0.15(6 + x)
1.2 = 0.9 + 0.15x
1.2 - 0.9 = 0.15x
0.3 = 0.15x
x = 0.3 / 0.15
x = 2
Therefore, you need to add 2 ounces of water to the 6-ounce, 20% acid solution to obtain a 15% acid solution.