posted by Kim .
If the density of ice is 0.92 g/cm^3, what percent of an ice cube’s (or iceberg’s) mass is above water.
The density of water is 1 g/cm^3.
Archimedes' principle says that the "buoyancy" (the upward force) is equal to the weight of water that is displaced.
You're only given the density. Therefore, you can assume whatever mass of ice that you wish. If you pick 1 gram of ice, the volume of ice will be
1 gram / (0.92 g/cm^3) = 1.087 cm^3
If you immerse this in water, it will displace 1 gram of water. Since the density of water is 1 gram/cc, it will displace 1 cm^3 of water.
You have 1 cm^3 of water being displaced, and a total ice volume of 1.087 cm^3. Therefore, 0.087 cm^3 of ice is above the water
0.087 cm^3 / 1.087 cm^3 x 100% = 8%