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1. Create an algebraic expression for

2. The cosx=4/5, x lies in quadrant 4. Find sin x/2

3.Determine all solutions in (0,2pie) for sin4xsin^2x=3,
cot^2v(3-1)cotx=v(3), cos^2x=cosx, and

4. Solve; sin(∏/2-x)=1/sec

5. Solve; cot+4x+2cot^2x+1=csc4x

6. Solve; tan(x+∏/x=(√(3)+3tanx)/(3-√(3)tanx

  • Math-Trig -

    Wow! You actually want somebody to do that assignment for you, without showing any effort on your part?

    I will start off with #2, then you let us know some of your steps and work

    use cos 2A = 1 - 2sin^2 A
    then cos x = 1 - 2sin^2 x/2
    4/5 = 1 - 2sin^2 x/2

    solve for sin x/2
    you will end up with sin x/2 = ±1/√10
    but you are told that x is in quadrant IV, so x/2 must be in quadrant II and
    sin x/2 = 1/√10

  • Math-Trig -

    Ok, so because sin=opp/hyp and sec=hyp/adj it will be √10/

  • Math-Trig -

    no, because I solved the equation 4/5 = 1 - 2sin^2 x/2

    2sin^2 x/2 = 1 - 4/5
    sin^2 x/2 = 1/10
    take √ of both sides
    sin x/2 = ± 1/√10

    why are you talking about secant?
    the problem dealt only with sines and cosines.

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