# Math-Trig

posted by .

1. Create an algebraic expression for
sin(arccosx-arcsin3x)

2. The cosx=4/5, x lies in quadrant 4. Find sin x/2

3.Determine all solutions in (0,2pie) for sin4xsin^2x=3,
cot^2v(3-1)cotx=v(3), cos^2x=cosx, and
tan^2x-6tanx+4=0

4. Solve; sin(∏/2-x)=1/sec

5. Solve; cot+4x+2cot^2x+1=csc4x

6. Solve; tan(x+∏/x=(√(3)+3tanx)/(3-√(3)tanx

• Math-Trig -

Wow! You actually want somebody to do that assignment for you, without showing any effort on your part?

I will start off with #2, then you let us know some of your steps and work

use cos 2A = 1 - 2sin^2 A
then cos x = 1 - 2sin^2 x/2
4/5 = 1 - 2sin^2 x/2

solve for sin x/2
you will end up with sin x/2 = ±1/√10
but you are told that x is in quadrant IV, so x/2 must be in quadrant II and
sin x/2 = 1/√10

• Math-Trig -

Ok, so because sin=opp/hyp and sec=hyp/adj it will be √10/

• Math-Trig -

no, because I solved the equation 4/5 = 1 - 2sin^2 x/2

2sin^2 x/2 = 1 - 4/5
sin^2 x/2 = 1/10
take √ of both sides
sin x/2 = ± 1/√10

why are you talking about secant?
the problem dealt only with sines and cosines.

## Similar Questions

1. ### Confused! Pre-Cal

Verify that each equation is an identity.. tan A= sec a/csca I have notes (i wasn't here that day and teacher refuses to reteach) but I don't understand them here is the notes... Problem w/ same directions: Cos x= cotx/csc x = Cosx/Sin …
2. ### trig

express this in sinx (1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?
3. ### Trigonometry.

( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx) Good one! Generally these are done by changing everything to sines and cosines, unless you see some obvious identities. Also generally, it is best to start with the more complicated side …
4. ### TRIGONOMETRY *(MATHS)

Q.1 Prove the following identities:- (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinx-cosx)/sec^3x-cosec^3x = sin^2xcos^2x.
5. ### TRIG..............

Q.1 Prove the following identities:- (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinx-cosx)/sec^3x-cosec^3x = sin^2xcos^2x.

7. ### Trig Identities

Proving identities: 1) 1+ 1/tan^2x = 1/sin^2x 2) 2sin^2 x-1 = sin^2x - cos^2x 3) 1/cosx - cosx = sin x tan x 4) sin x + tan x =tan x (1+cos x) 5) 1/1-sin^2x= 1+tan^2 x How in the world do I prove this...please help... I appreciateyour …
8. ### Trigonometry

Prove the following trigonometric identities. please give a detailed answer because I don't understand this at all. a. sin(x)tan(x)=cos(x)/cot^2 (x) b. (1+tanx)^2=sec^2 (x)+2tan(x) c. 1/sin(x) + 1/cos(x) = (cosx+sinx)(secx)(cscx) d. …
9. ### Precalculus/Trig

I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1-cosx Simplified: cosx + sin^3x/sin^3x = cscx/1-cosx I don't know …
10. ### Studying for math test

Multiply; then use fundamental identities to simplify the expression below and determine which of the following is not equivalent. (sin x + cos x) ^2 a. 1+2sinxcosx b. sec^2x−tan^2x+2cosxsinx c. sec x + 2 sin x/sec x d. sin^2x+cos^2x …

More Similar Questions