Okay,
mol KHP = (0.7719)(mol KHP/204.2g KHP) = .0038mol
Since this is a titration then the moles of NaOH = the moles of KHP
M = mol/L
M = .0038mol/02637
M = 0.01441
Two minor problem.
First, you have rounded 0.7719/204.2 incorrectly. You have 4 significant digits in both the numerator and denominator; therefore, you are allowed 4 s.f. in the answer. Unless the answer is 0.003800, your rounding makes the answer wrong. And it isn't 0.003800. I get 0.003780.
Calculator tip #1--To get around the rounding errors, I don't copy the answer down and start over when I divide by the 26.37 mL of NaOH. I just leave that number of 0.0038781175 etc etc to nine places in my calculator. Not only does it save time, because I don't need to copy it and re-enter it into the calculator, but it preserves the digits, whatever they may be. All of them may not be s.f. but that really doesn't matter. Whatever the number of s.f. I know they are in the calculator.
Second--I think the division is off by a factor of 10. I get 0.1433.
To calculate the molarity (M) of a solution, you need to know the number of moles present and the volume of the solution. In this case, you have already determined the number of moles of KHP to be 0.0038 mol.
Now, to calculate the molarity, you need to divide the number of moles by the volume of the solution in liters. However, it seems that you have not provided the volume of the solution in your question. Please provide the volume of the solution so that I can help you calculate the molarity.