In 2003, the probability that a randomly chosen bag of cement from the world supply was consumed in the U.S. was .05, while the probability that it was consumed in China was .45. What is the probability that a randomly chosen bag of cement was consumed in neither country?
There is no joint probability, that is, it cannot be consumed in China and US.
Therefore, Prob(notconsumedChinaorUS)=1-prob(US)-prob(China)=.50
According to the New York Times/CBS poll of March, 2005, 87% agreed that it should be the government's responsibility to provide a decent standard of living for the elderly, and 54% agreed that it would be a good idea to invest part of their Social Security taxes on their own.
What is the smallest percentage of people who could have agreed with both statements?
What is the largest percentage of people who could have agreed with both statements?
To find the probability that a randomly chosen bag of cement was consumed in neither the U.S. nor China, we need to subtract the probabilities of it being consumed in the U.S. and China from 1.
Let's denote:
P(U) = Probability of a randomly chosen bag of cement being consumed in the U.S. = 0.05
P(C) = Probability of a randomly chosen bag of cement being consumed in China = 0.45
The probability of it being consumed in neither country is given by:
P(neither) = 1 - P(U) - P(C)
P(neither) = 1 - 0.05 - 0.45
= 1 - 0.5
= 0.5
Therefore, the probability that a randomly chosen bag of cement was consumed in neither the U.S. nor China is 0.5.