2r-5s=-14
5r+2s=23
I know the answer is s=14 and r=3 but how do I wirte this down on my assignment? If I entr it wrong, I will get it wrong.
Opps I meant s= 4
The answer that you think you know is wrong. It will make no difference how you enter it; it will still be wrong.
4r -10s = -28
25r +10s = 115
29r = 87
r = 3
6 - 5s = -14
5s = 20
s = 4
You need a tutorial on how to solve simultaneous equations. Concentrate on learning the method.
I missed your correction and apologize for my remark. You obviously do know how to do this type of problem. I would just report the result as r=3 and s=4
To write down the solution for these equations, you can follow these steps:
Step 1: Solve one of the equations to express one variable in terms of the other variable.
Let's solve the first equation, 2r - 5s = -14, for r:
2r = 5s - 14
Divide both sides by 2:
r = (5s - 14)/2
Step 2: Substitute the value obtained in step 1 back into the other equation.
Substituting r in the second equation, we have:
5((5s - 14)/2) + 2s = 23
Multiply through by 2 to get rid of the fraction:
5(5s - 14) + 4s = 46
25s - 70 + 4s = 46
Combine like terms:
29s - 70 = 46
Add 70 to both sides:
29s = 116
Divide both sides by 29:
s = 116/29
s = 4
Step 3: Substitute the value of s back into the equation obtained in step 1 to find the value of r.
Using the equation r = (5s - 14)/2, we have:
r = (5(4) - 14)/2
r = (20 - 14)/2
r = 6/2
r = 3
So the solution to the system of equations is r = 3 and s = 4.
To write this down on your assignment, you can simply write:
r = 3
s = 4
Make sure to clearly label the variables and their corresponding values, so there is no confusion.