Is this correct???

2. Trains A and B are traveling in the same direction on parallel tracks. 2. Train A is travelling at 100 miles per hour and train B is traveling at 125 miles per hour. Train A passes a station at 5:10 A.M. If train B passes the same station at 5:22 A.M, at what time will train B catch up to train A?

100(t) + 20 = 125(t)
100t + 20 = 125t
25t = 20
t = 20/25 = 4/5 hr X 60 = 48 min
5:22 + 48 = 6:10 they pass each other

Proof
100(4/5) + 20 = 125(4/5)
80 + 20 = 4(25)
100 = 100

Agree

Thank you!!!

Yes, the solution you provided is correct. You correctly set up the equation to represent the relationship between the distances traveled by the two trains and their respective speeds. By solving for "t," which represents the time it takes for Train B to catch up to Train A, you found that "t" is equal to 4/5 of an hour or 48 minutes. Adding this time to the time Train B passed the station at 5:22 A.M., we get the time they will pass each other, which is 6:10 A.M.

You also demonstrated a proof by substituting the values back into the equation and confirming that the equation holds true. This confirms the accuracy of your solution. Well done!