A 15.0 resistor and a 20.0 resistor are connected in parallel. A 5.00 resistor is connected across a 1.00 10^2-V battery. What is the current flowing through the 20.0 resistor?
A. 1.21 A
B. 3.15 A
C. 5.00 A
D. 6.84 A
I don't think it's C....
If I read this correctly, all three resistors are in parallel, so the current in the 20 ohm resistor is 100/20 amps.
The wording is confusing on the 5 ohm reistor connection.
I know, I think they left out words or something... I'm just going to put C...
To find the current flowing through the 20.0 resistor, we can use Ohm's Law, which states that the current flowing through a resistor is equal to the voltage across the resistor divided by its resistance.
First, we need to determine the total resistance of the circuit. Since the 15.0 resistor and the 20.0 resistor are connected in parallel, we can use the formula for combining resistors in parallel:
1/RTotal = 1/R1 + 1/R2
where RTotal is the total resistance, R1 is the resistance of the first resistor (15.0 ), and R2 is the resistance of the second resistor (20.0 ).
1/RTotal = 1/15.0 + 1/20.0
To simplify the calculations, we can find the common denominator and add the fractions:
1/RTotal = (20 + 15)/(15 × 20)
= 35/300
= 7/60
Taking the reciprocal of both sides gives:
RTotal = 60/7
≈ 8.571
Now, we can use Ohm's Law to find the current flowing through the 20.0 resistor. We know that the voltage across the resistor is given as 10^2 V (100 V), and the resistance is 20.0 :
I = V/R
= 100/20.0
= 5.00 A
Therefore, the current flowing through the 20.0 resistor is 5.00 A. Therefore, the correct answer is A.