The following equation describes the oxidation of an acidified solution of sodium oxalate (Na2C2O4) by potassium permanganate(KMnO4)
5C2O4 + 2MnO4 + 16H2SO4 --> 10CO2 + 2Mn + 16HSO4 + 8H20
What volume of 0.127M sodium oxalate in sulphuric acid will react with 3.57g of potassium permanganate?
Convert 3.57 g KMnO4 to moles. mols = grams/molar mass.
Using the coefficients in the balanced equation, convert mols KMnO4 to mols Na2C2O4.
molarity Na2C2O4 = mols/L. YOu know mols from the above calculation, you know M, calculate volume.
Post your work if you get stuck.
0.071L
M KMnO4 = 158.0339g/mol
1 mol
3.57g X -----------------
158.0339g KMnO4
5 mol C2O4-
= 0.02259009 mol KMnO4 X -------------
2 mol KMnO4
1 L
=0.056475225 mol C2O4-X ---------------
0.127 mol C2O4-
= 0.445 L
Woops sorry about the spacing. I didn't realize it would come out like that. Hope you can read it.
To solve this problem, we need to use the balanced chemical equation and the concept of stoichiometry.
Let's break down the problem into steps:
Step 1: Find the number of moles of potassium permanganate (KMnO4):
To find the number of moles, we'll use the formula:
Number of moles = mass / molar mass
The molar mass of KMnO4 is:
(1 x K) + (1 x Mn) + (4 x O) = 39.1 + 54.9 + (4 x 16.0) = 39.1 + 54.9 + 64 = 158 g/mol
Now, we can calculate the number of moles of KMnO4:
Number of moles = 3.57 g / 158 g/mol = 0.0226 mol
Step 2: Use the balanced chemical equation to determine the stoichiometric ratio between KMnO4 and Na2C2O4:
According to the balanced equation, the ratio between KMnO4 and Na2C2O4 is 2:5. This means that for every 2 moles of KMnO4, we need 5 moles of Na2C2O4.
Step 3: Calculate the number of moles of Na2C2O4 needed:
Since the ratio is 2:5, we can set up the following equation:
(2 mol KMnO4 / 5 mol Na2C2O4) = (0.0226 mol KMnO4 / x mol Na2C2O4)
Solving for x, we get:
x = (5 mol Na2C2O4 * 0.0226 mol KMnO4) / 2 mol KMnO4 = 0.0565 mol Na2C2O4
Step 4: Calculate the volume of the 0.127M sodium oxalate solution:
To do this, we'll use the formula:
Volume = moles / concentration
The concentration is given as 0.127 M and the number of moles we just calculated is 0.0565 mol.
Volume = 0.0565 mol / 0.127 mol/L = 0.445 L
So, the volume of the 0.127M sodium oxalate solution needed to react with 3.57g of potassium permanganate is 0.445 liters.