Help me solve this problem please, I have tried so many time.I can not seem to get the problem right.
x +12 <-8 or x+12>2
x+ 12 < -8 =x +12 > 2
x =4 > -10 is this right
x +12 < -8
Subtract 12 from both sides.
x < -20
x + 12 > 2
x > -10
Both inequalities cannot be true at the same time, for obvious reasons.
since the operator was "OR"
the solution is
x < -20 OR x > -10
had the operator been "AND" there would have been no solution.
To solve the given problem, which states "x + 12 < -8 or x + 12 > 2," we need to find the range of values for x that satisfy the inequality.
Let's break it down into two separate inequalities:
1. x + 12 < -8
2. x + 12 > 2
For the first inequality, we subtract 12 from both sides to isolate x:
x + 12 - 12 < -8 - 12
x < -20
So, the range of values for x that satisfy the first inequality is x < -20.
Now, let's solve the second inequality:
x + 12 - 12 > 2 - 12
x > -10
The range of values for x that satisfy the second inequality is x > -10.
Combining the two solutions, we have:
x < -20 or x > -10.
Therefore, any value of x that is less than -20 or greater than -10 will satisfy either of the two inequalities given in the original problem.