What is the Lewis dot structure for LiF?

Is it Li - F with 2 dots on each side of F?

Close. F should have two dots on the left side, two on the top, two on the right side and two on the bottom for a total of 8 dots. Then it will have a negative charge while the Li ion, which has no electrons on it, will have a positive charge.

The Lewis dot structure for LiF (Lithium Fluoride) is slightly different from what you have described. Here's how you can determine it:

1. Identify the number of valence electrons:
Lithium (Li) is in Group 1 of the periodic table, so it has 1 valence electron. Fluorine (F) is in Group 17, so it has 7 valence electrons.

2. Place the atoms:
Since Li has only 1 valence electron, it is typically written as Li+. This means it loses its valence electron to achieve a stable configuration. On the other hand, F needs only 1 additional electron to achieve a stable configuration. Therefore, the electron configuration for F will be represented by F-.

3. Draw the structure:
To represent the sharing or transfer of electrons between atoms, we use dots (representing valence electrons) around the atomic symbol. Since Li has lost its valence electron, it will have no dots. F, on the other hand, will have 8 dots (including six dots around the symbol and two additional dots, one on each side).

So, the correct Lewis dot structure for LiF is:
Li+: no dots
F-: six dots (arranged in pairs) around the symbol.

Remember that the Lewis dot structure represents the valence electrons only, not the overall charge of the atom.

The Lewis dot structure of LiF can be shown as Li with a single dot on the left side and an F with six dots surrounding it. In LiF, Lithium (Li) has only one valence electron, so it is depicted as a single dot, and Fluorine (F) has seven valence electrons, so it is shown with six dots surrounding it. The dots represent the valence electrons of each atom. Therefore, the correct Lewis dot structure for LiF is Li • - F • • • • •.