pre calc
posted by jaz .
The terminal side of an angle in standard position goes through the poin (2,5). Find the values of the 6 trig function
sin
cos
tan
csc
sec
cot

did you make a diagram?
you would have a rightangled triangle in the second quadrant with x=2 and r=5
so
x^2 + y^2 = r^2
4 + y^2 = 25
y = ± √21
but we are in quadrant II, so y = +√21
now, knowing the trig rations in terms of x,y, and r, your question is easy
e.g. tan(angle) = y/x =  √21/2
sec(angle) = r/x =  5/2
you do the rest.