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The length of a rectangle is 5 cm more than twice the width. The perimeter of the rectangle is 34 cm. Find the dimensions of the rectangle.

  • math -

    if you let the width be w cm
    isn't the length 2w + 5 ?

    now form the equation for
    perimeter = 34

    let me know what you get.

  • math -

    aren't you supposed to form it for the width?

  • math -

    but forming one for the perimeter would be 2L+2w=34.

  • math -

    << but forming one for the perimeter would be 2L+2w=34 >>

    precisely!

    but didn't it say " The length of a rectangle is 5 cm more than twice the width"
    or
    l = 5 + 2w , as I stated in my first reply.

    so 2l + 2w = 34
    2(5+2w) + 2w = 34
    10 + 4w + 2w = 34
    6w = 24
    w = 4
    then
    l = 5 + 2w
    = 5 + 8 = 13

    check: is 13 five more than twice 4??
    is 2(4) + 2(13) = 34 ?

    mmmh?

  • math -

    thank you, i get it now

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