math
posted by Angie .
The length of a rectangle is 5 cm more than twice the width. The perimeter of the rectangle is 34 cm. Find the dimensions of the rectangle.

if you let the width be w cm
isn't the length 2w + 5 ?
now form the equation for
perimeter = 34
let me know what you get. 
aren't you supposed to form it for the width?

but forming one for the perimeter would be 2L+2w=34.

<< but forming one for the perimeter would be 2L+2w=34 >>
precisely!
but didn't it say " The length of a rectangle is 5 cm more than twice the width"
or
l = 5 + 2w , as I stated in my first reply.
so 2l + 2w = 34
2(5+2w) + 2w = 34
10 + 4w + 2w = 34
6w = 24
w = 4
then
l = 5 + 2w
= 5 + 8 = 13
check: is 13 five more than twice 4??
is 2(4) + 2(13) = 34 ?
mmmh? 
thank you, i get it now
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