In 1989, Carl Lewis established a world record when he ran the 100 meter dash in 9.92 seconds. What was his average speed(in m/s) for the race? Remember to include your data, equation, and work when solving this problem.
I am not sure how to do this problem. Please help!!
Well, calculating Carl Lewis's average speed is no sweat... or maybe it's just a little bit of sweat. Anyway, let's get to it!
To find the average speed, we need to divide the distance covered by the time taken. In this case, the distance is 100 meters, and the time is 9.92 seconds.
Average speed = distance / time
Plugging in the values, we get:
Average speed = 100 meters / 9.92 seconds
And when we do the math:
Average speed ≈ 10.08 meters per second
So, Carl Lewis's average speed for the race was approximately 10.08 m/s. Phew, that's some speedy running!
To find Carl Lewis's average speed for the race, we need to determine the distance he covered in meters and divide it by the time it took him to run the race.
Given:
Time = 9.92 seconds
The distance covered in a 100-meter dash is 100 meters.
Average Speed = Distance/Time
Average Speed = 100 meters / 9.92 seconds
Calculating the average speed:
Average Speed = 100 meters / 9.92 seconds
Average Speed = 10.08 meters/second
Therefore, Carl Lewis's average speed in the 100-meter dash was approximately 10.08 m/s.
To find Carl Lewis's average speed, we need to use the formula for average speed:
Average Speed = Distance / Time
In this case, the distance is 100 meters (as mentioned, it is a 100-meter dash) and the time is given as 9.92 seconds.
Plugging in the values:
Average Speed = 100 meters / 9.92 seconds
To find the average speed in meters per second (m/s), we divide the distance by the time.
Now, we can calculate the average speed:
Average Speed = 100 meters / 9.92 seconds
Average Speed ≈ 10.08 m/s
Therefore, Carl Lewis's average speed for the 100-meter dash was approximately 10.08 m/s.
Remember, to solve similar problems, you should always use the formula for average speed: Average Speed = Distance / Time.