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write each expression without using the factorial symbol.

1)(n-3)!
-----
n!

2) (n+4)!
-------
(n+2)!

  • math -

    I will do one. Take the greater number, and expand it. for instance, the first

    (n-3)!/(n*(n-1)(n-2)(n-3)!)

    the (n-3)! terms divide out..

    1/(n)(n-1)(n-2)

  • math -

    then the second one would be
    (n+4)!/((n+1)(n+2)(n+3)(n+4)(n+2)!)
    =
    1/(n+1)(n+2)^2 (n+3) ?

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