diffeq
posted by Mischa .
how do i find the bifurcation for this:
d^x/dt^2 = .3 x  (x  1)/((x  1)^2 + a^2)^(3/2)  (x + 1)/((x + 1)^2 + a^2)^(3/2)
we've tried using mathematica but it just runs forever...

diffeq 
bobpursley
Well by inspection,
dx/dt=.3/2 x^2  1/2((x1)^2+ a^2)^.5+1/2 (((x+1)^2+a^2)^.5
and then
x= 1/20x^3 1/3 ((x1)^2+ a^2)^3/2 + you finish it.
Did I miss something?
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