# calculus

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what's the limit as n goes to infinity of (2 + 4/n^2)^(1/3)

• calculus -

as n --> ∞ , 4/n^2 ---> 0
(2+0)^(1/3)
which is the cuberoot of 2 or appr. 1.2599

• calculus -

thnx

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