A 200 mg/dl solution was diluted 1:10. This diluted solution was then additionally diluted 1:5. What us the concentration of the final dilution?

The resulting concentration is 1/10 x 1/5 = 1/50 of the original. That would be 4 mg/dl

1/10x1/5= 1/50

200/50= 4

Isn't it diluted by a factor of 50?

To find the concentration of the final dilution, we need to multiply the dilution factors.

First, the original 200 mg/dl solution was diluted 1:10. This means 1 part of the original solution was mixed with 10 parts of the diluting solvent. Therefore, the concentration of the first dilution is 200 mg/dl * (1/10) = 20 mg/dl.

Next, the first dilution was further diluted 1:5. This means 1 part of the first dilution was mixed with 5 parts of the diluting solvent. So, the concentration of the final dilution is 20 mg/dl * (1/5) = 4 mg/dl.

Therefore, the concentration of the final dilution is 4 mg/dl.