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Find the vertex and graph of y = x2 + 5?
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Identify the vertex and the axis of symmetry for the graph of y=5(x-2)^2 + 3.
a) vertex (2,3); x = -2 b) vertex (-2,-3); x = 2 c)
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Let f(x) = 2(x- h1)*2 + k1 and g(x) = ( x- h2)*2 + k2, where h1, h2,k1,k2. The vertex of the graph of f is at (m,-m*2) and the
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f(x) = -3(x^2+4x) - 5 = -3(x^2+4x+4) - 5 +3(4) = -3(x+2)^2 + 7 so, the vertex is at (-2,7) clearly,
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Write an equation for the translation so the graph has the given vertex.
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To find the equation for the translation so that the graph has the given vertex, we need to
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Graph is a complete graph -it called K6- IT HAS 6 VETICES. also, every vertex is connected to every other vertex.
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Identify the vertex of the graph. Tell whether it is a minimum or a maximum.
-8 -4 4 8 -8 -4 4 8 x y x y graph Question content
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The vertex of the graph is (0, -8) and it is a minimum.
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A graph is constructed iteratively according to the following algorithm. The graph starts as a single vertex. With probability
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To find the value of p when the expected number of vertices in the graph is 100, we can start by
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1. What are the coordinates of the vertex of the graph? Is it a maximum or minimum?
3. How is the graph of y = –2x2 – 4
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1. what graph? 3. -2x2-4 is 4 units below -2x2 4. wich func.?
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Consider the function f(x)=4x^2+8x-10 and g(x)=5x^2+10x-1
1 function f is a graph whose vertex is_____ the vertex for the graph
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The vertex for the function f is higher than the vertex for the function g. The vertex for the
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The graph of the function g(x) has the same shape and direction of opening as the graph of f(x)= 3(x-2)^2+9. The graph of g(x)
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the vertex of f(x) is (2,9) The vertex of g(x) is to the right 2 units and 5 units down, so its
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