math calculus
posted by sarah .
Hi could someone please explain to me how i would use the chain rule
dy/dx = dy/du(du/dx) to solve for
y= sin(x+y)  im looking for dy/dx
i don't understand the steps
thanks

let u = x + y
du/dx = 1 + dy/dx
then y = sin u
and dy/dx = cosu du/dx
= cosu (1 + dy/dx)
= cosu + dy/dxcosu
dy/dx  dy/dxcoxu = cosu
dy/dx = cosu/(1  cosu)
= cos(x+y)/( 1  cos(x+y)
personally I would bypass all that subbing and my second line would be
dy/dx = cos(x+y)(1 + dy/dx)
etc. 
alright, but i don't know how i would now isolate for dy/dx?
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