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How do you find the critical numbers and the end points of this function:

i calculated the critical numbers as x=-1 and x=2 is this right?!?!

  • Calculus -

    great so far.
    now find f(2) and f(-1) for the y values of your critical points.

    unless there is a domain given for your x's , there are no "end points" for your function.

  • Calculus -

    If by "ritical numbers" you mean where the function has a local maximum or minimum, that would be where
    f'(x) = 6x^2 -6x -12 = 0
    x^2 -x -2 = 0
    (x+1)(x-2) = 0
    yes, -1 and 2 are correct.
    f(x) has no end points or absolute maximum or minimum. It goes to + and - infinity when x does the same

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