Hi!!

What is the y intercept for the slope 8/5? (Or, what is the y intercept for the equation y=8/5+b?)

Please Help!!
Thank You!!

If you are talking about a straight line with slope 8/5, the equation is

y = (8/5)x + b
You left out the x.
The y-intercept (where the line crosses the y axis) is b.

Did you mean to type

y=(8/5)x + b ?

the y-intercept-slope form looks like this:
y = mx + b

the m is the slope, in your case 8/5
and the b is the y-intercept.
You did not state a y-intercept.

e.g. had the equation been
y = (8/5)x + 12

your line would have a slope of 8/5 and a y-intercept of 12, i.e., it would pass through the point (0,12) on the y-axis.

Hi there!

To find the y-intercept for the equation y = (8/5)x + b, you need to know that the y-intercept occurs when x = 0. In other words, it's the point where the line crosses or intersects the y-axis.

To find the value of b, you can substitute x = 0 into the equation and solve for y. Let's do that:

y = (8/5)(0) + b
y = 0 + b
y = b

So, we can see that when x = 0, y = b. This means that the y-intercept is the value of b in the equation.

Therefore, the y-intercept for the equation y = (8/5)x + b is simply b.