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What is a "Slope, Midpoint & Distance"? This is the problem:
(7,3) and (-1,-4)

slope = (Y2-Y1)/(X2-X1)
=(-4-3)/-1-7
= -7/-8
=7/8

midpoint
x = X1 + (1/2)(X2-X1) = 7 +(1/2)(-8)
= 7-4
= 3
do y the same way

d^2 = (Y2-Y1)^2 + (X2-X1)^2
d^2 = 49+64 = 113
d = sqrt (113)

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