calculus

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integrate log base 10 x / x dx


i don't understand this

  • calculus -

    log(10)x = log(10)e*log(e)x
    = 0.4342945 ln x

    So, integrate 0.4342945 ln x /x

    It will help to know that the integral of (ln x)/x is (ln x)^2/ 2.

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