calculus
posted by kevin .
integrate log base 10 x / x dx
i don't understand this

calculus 
drwls
log(10)x = log(10)e*log(e)x
= 0.4342945 ln x
So, integrate 0.4342945 ln x /x
It will help to know that the integral of (ln x)/x is (ln x)^2/ 2.
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