Chemistry
posted by Chopsticks .
A sample of Oxygen has occupies 1.00x10^6mL at 575mm Hg is subjected to a pressure of 1.25atm. What will the final volume of the sample be if the temperature is held constant
v2=(p1)(p2)/p2
I'll have to convert 1.25atm to mm first
1.25atm*760mm/1.0atm = 950. mm
V2=(575mm)(1.00x10^6mL)/950.mm
=6.05x10^5
Can you check my math and method?

Also:
A gas has a volume of 450.0 mL. If the temperature is held constant, what volume would the gas occuply if the pressure were doubled? 
Okay, for the second part I got 1.80x10^3 mL

I worked the 1st problem a different way and obtained the same answer. For #2, if the pressure is doubled won't the volume be halved? And your answer isn't half of what you started with. Just to make the problem simple, however, if you want to do it with numbers, just put in 1 for P1 and 2 for P2.

ohh i got 225.

That's much better.

Thanks haha. I had that answer for my paper, but on part b, it asked for 1/4 of the orginial pressure. And if that was the case, then 1.80x10^3 mL would be correct?
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