posted by lt .
How do I solve:
log6 (x^2-5x) = 1
I really don't know how to do these or even start
I assume the number immediately after log is the base of the log.
log6 (x^2-5x) = 1 is equivalent to writing
6^1 = x^2-5x = 6
Rewrite as a polynomial
x^2 -5x -6 = 0
(x-6)(x+1) = 0
x = 6 or -1
Do the others the same way. Rewrite the equation containing the log term as a polynomial, and factor it.