college
posted by Jess .
The square of an integer is 12 more than the integer. Find the integer

x + 12 = x^2
x^2  x  12 = 0
(x + 3)(x  4) = 0
x + 3 = 0
x = 3
This obviously doesn't work.
x  4 = 0
x = 4
This doesn't work, but since both the positive and negative values of integers yield the same value when squared, let's try 4.
4^2 = 16
This is 12 more than the original integer 4. 
from Pink Floyd's
(x + 3)(x  4) = 0
x = 3 or x=4
check: is (3)^3 12 more than 3 ? yes!
is (4^) 12 greater than 4 ? Yes!
so the numbers are either 4 or 3 
By George, you're right.. just a little bit of math errors on my part.
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