posted by Bob .
A 0.1300 g iron ore sample was dissolved in hydrochloric acid and the iron was obtained as Fe2+(aq). The iron solution was titrated with Ce4+ solution according to the balanced chemical reaction shown below. After calculation, it was found that 0.0259 g of iron from the ore reacted with the cerium solution.
Ce4+(aq) + Fe2+(aq) -> Ce3+(aq) + Fe3+(aq)
Calculate the mass percent of iron in the original ore sample. Please round your answer to the tenths place
0.0259 x 100/ 0.1300 = 19.9%
I think i did this problem correctly, but I wanted it to be approved by an expert.