A concave mirror forms a real image at 17.0 cm from the mirror surface along the principal axis. If the corresponding object is at ta distance of 36.0 cm, what isi the mirror's focal length?

Question

A concave mirror forms a real image at 17.0 cm from the mirror surface along the principal axis. If the corresponding object is at ta distance of 36.0 cm, what isi the mirror's focal length?

let u be the object distance
let v be the image distance

v=17 cm
u=36 cm

1/f = 1/u + 1/v
= u+v
___
uv

so f=uv
____
u+v

= 17*36
_____
17+36

= 11.55cm

is this done correctly?

Answer 1

Yes, your calculation is correct. You correctly used the mirror formula, which is given by 1/f = 1/u + 1/v, where f is the focal length, u is the object distance, and v is the image distance. By substituting the given values, u = 36 cm and v = 17 cm, you calculated f to be approximately 11.55 cm.

Answer 2

Yes, you have correctly calculated the focal length of the concave mirror. The focal length is calculated using the formula 1/f = 1/u + 1/v, where u is the object distance and v is the image distance. By substituting the given values, you have correctly found the focal length as 11.55 cm.