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consider the following sample statistics from a population that is aproximatly normal. n=15, s= 7.92,level of confidence is 99 %

Calculate the margin of error( round to the nearest hunderth)

  • statistics -

    Margin of error = + or - (z-value)(s/√n)
    ...where z-value is found using a z-table for 99% confidence, s = standard deviation, and n = sample size.

    Look up the value in the table, then substitute what you know into the formula.

    I hope this will help get you started.

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