I have this figure of a square QRST with an equilateral triangle PQT sitting on top of the square. The figure looks like a little house...
My question is if PQ equals 6 cm, then what is the area of the square?
Do I need to find the area of the triangle to figure this out? Do I use 1/2(B)(H) to find area of triangle and do I use a2 to find area of square....Please help
If the triangle is equalaterial, then QT is also six, so the area of the square is 36.
To find the area of the square in the figure, you do not need to find the area of the triangle. You can directly calculate the area of the square.
The area of a square is given by the formula A = side length × side length, or A = s^2.
To find the side length of the square in this figure, you can use the fact that it is equal to the length of one of the sides of the equilateral triangle.
Given that PQ, which is also a side of the square, is equal to 6 cm, we can conclude that the side length of the square (PQ) is 6 cm.
Now, you can substitute the value of the side length (s) into the formula for the area of the square:
A = s^2 = 6 cm x 6 cm = 36 cm^2
Therefore, the area of the square is 36 square cm.