Calculate the sodium ion concentration when 80.0 mL of 4.5 M sodium carbonate is added to 30.0 mL of 1.0 M sodium bicarbonate.
how do i solve this I don't really know where to begin..
is there a formula for finding concentration because we don't learn this in class we basically teach ourselves
thanks!
The concn unit you have been using, which is moles/L or molarity, is what you use for this. Calculate the moles Na ion from Na2CO3, then calculate Na ion from NaHCO3, add the moles together, then divide by the total volume and you have will molarity of Na ion in the solution.
To solve this problem, you can use the formula for calculating the concentration of a solution:
Concentration (M) = moles of solute / volume of solution (L)
Given:
Volume of sodium carbonate solution = 80.0 mL = 0.080 L
Concentration of sodium carbonate solution = 4.5 M
First, calculate the moles of sodium carbonate:
Moles of sodium carbonate = Concentration * Volume
Moles of sodium carbonate = 4.5 M * 0.080 L
Next, calculate the moles of sodium bicarbonate:
Volume of sodium bicarbonate solution = 30.0 mL = 0.030 L
Concentration of sodium bicarbonate solution = 1.0 M
Moles of sodium bicarbonate = Concentration * Volume
Moles of sodium bicarbonate = 1.0 M * 0.030 L
Now, to find the total moles of sodium ions:
Total moles of sodium ions = moles of sodium carbonate + moles of sodium bicarbonate
Finally, calculate the concentration of sodium ions:
Concentration of sodium ions = Total moles of sodium ions / total volume of solution
Now you have the steps to solve the problem. Just plug in the given values and perform the calculations to find the concentration of sodium ions.
To solve this problem, you will need to use the concept of molarity and the formula that relates it to volume and concentration. Here's how you can approach the problem step by step:
Step 1: Write down the given information:
- Volume of sodium carbonate solution (V1): 80.0 mL
- Concentration of sodium carbonate (C1): 4.5 M
- Volume of sodium bicarbonate solution (V2): 30.0 mL
- Concentration of sodium bicarbonate (C2): 1.0 M
Step 2: Convert the volumes to liters:
- V1 = 80.0 mL = 80.0 mL * (1 L / 1000 mL) = 0.080 L
- V2 = 30.0 mL = 30.0 mL * (1 L / 1000 mL) = 0.030 L
Step 3: Use the formula for calculating the concentration of a solution after mixing:
Cf = (C1 * V1 + C2 * V2) / (V1 + V2)
Cf represents the concentration of the resulting solution.
Step 4: Substitute the values into the formula:
Cf = (4.5 M * 0.080 L + 1.0 M * 0.030 L) / (0.080 L + 0.030 L)
Step 5: Simplify and calculate:
Cf = (0.36 M + 0.03 M) / 0.11 L
Cf = 0.39 M / 0.11 L
Cf ≈ 3.54 M
Therefore, the resulting sodium ion concentration is approximately 3.54 M.
Remember to always take care with units and conversions in order to obtain accurate results.