physics
posted by ramesh reddy .
Please help me to solve this problem.
A body is projected vertically upwards with a velocity 20m/s. find the maximum height reached by the body.(g=10m/sec2)

v = Vi + a t
we want the top where v = 0
Vi = +20
a = 10
so
0 = 20  10 t
t = 2 seconds to top
h = Vi t + (1/2) a t^2
h = 20 (2)  (1/2)(10) (2)^2
h = 40  20
h = 20 
20M
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