betty is now three times as old as mike, but in five years she will be only twice as old as mike. how old is mike right now?
i don't get what your suppose to do
NOW:
MIke - x
Betty - 3x
In 5 Years:
MIke - x+5
Betty - 3x+5
but it said: (3x+5) = 2(x+5)
solve for x
x=3y
and
x+5=2y
solve for y in 1st and carry to 2nd eq
y=x/3
x+5=2(x/3)
solve for x
check answer
solve and comparison:
a)4x-9y+4
6x+15y=-13
im so lost!!!!!
mary is 4 and mike is 12
To solve this problem, you can use algebraic equations. Let's assign variables to Betty and Mike's current ages. Let's say Betty's age is B and Mike's age is M.
Given that Betty is now three times as old as Mike, we can write the equation: B = 3M.
We are also given that in five years, Betty will be only twice as old as Mike. In five years, Betty's age will be B + 5, and Mike's age will be M + 5.
So, we can write the second equation: B + 5 = 2(M + 5).
Now you have a system of two equations with two variables:
1) B = 3M
2) B + 5 = 2(M + 5)
To solve this system, we can substitute the value of B from the first equation into the second equation:
3M + 5 = 2(M + 5)
Now, simplify this equation:
3M + 5 = 2M + 10
Subtract 2M from both sides:
M + 5 = 10
Subtract 5 from both sides:
M = 5
So, Mike is currently 5 years old.