algebra 1
posted by Dippy .
Reiny I posted a question earlier (about 3:00) and I have a question about your solution. How did you get 4x? I came up with 8x which does not allow for anymore reduction. Please let me know how you did it. Thanks!

You had a 6x on the left, and a 2x on the right side. Add 2x to each side, giving on the left 4x and on the right zero.

x^3 + 3 x^2 2 x^2  6 x + 2 x^2 + 2 x = 0
note that 6x + 2 x = 4x
x^3 + 3 x^2 4 x = 0
x ( x^2 + 3 x  4) = 0
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