I don't know how to do these types of problems whatsoever.
1) It takes a small jet plane 4 hours less time than it takes a propeller-driven plane to travel from Glen Rock to Oakville. The jet plane averages 637 km/h while the propeller plane averages 273 km/h. How far is it from Glen Rock to Oakville?
2)An airplane took 2 hours to fly 600 km against a head wind. The return trip with the wind took 1 2/3 hours. Find the speed of the plane in still air.
Let d be distance.
d=637*Time
d=273*(Time+4)
set them equal to each other, and solve for time. Then solve for d.
2)
600=(Speed-headwind)*2
600=(Speed+headwind)1.66
divide the first equation by 2, and the second by 1.66
add the equations...
300+600/1.66 = 2*Speed
solve for speed
kjc
To solve these types of problems, we can use the formula:
Distance = Speed * Time
For the first problem, let's denote the distance from Glen Rock to Oakville as "d."
For the jet plane, the time it takes to travel this distance is given as 4 hours less than the time it takes for the propeller-driven plane. So, let's denote the time it takes for the jet plane as "t" and the time it takes for the propeller-driven plane as "t + 4."
Using the formula, we have the following equations:
For the jet plane:
Distance = Speed * Time
d = 637 * t
For the propeller-driven plane:
Distance = Speed * Time
d = 273 * (t + 4)
Now we can solve these equations simultaneously to find the value of "d," which represents the distance from Glen Rock to Oakville.
For the second problem, let's denote the speed of the plane in still air as "s."
Against the head wind, the plane took 2 hours to fly 600 km. So, using the formula, we have:
Distance = Speed * Time
600 = (s - wind speed) * 2
On the return trip with the wind, the plane took 1 2/3 hours. So we have:
Distance = Speed * Time
600 = (s + wind speed) * (5/3)
We can now solve these two equations to find the value of "s," the speed of the plane in still air.