Could you please help me with this thanks.
6a(-5 power)b(2nd power)c(-3 power)
Are you solving for anything? You can rewrite that as:
b^2/[(6a^5)(c^3)]
No it just says simplify
Then that should be your answer
Thanks for your help could you help me with this you use the equation a^2* b^2= c^2.
You have to find x so would x be a, b, or c I'm not sure cause it doesn't say on my paper.
I mean you have to find the x length so here are the numbers 25, and 7. So I did 25^2+7^2=c^2
Then I put 625+49= 674
Did I do this right??
That is the Pythagorean theorem, which states that:
in any right triangle, the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares whose sides are the two legs.
Of course, I'd be happy to help you with that! To simplify the expression:
6a^(-5)b^(2)c^(-3)
We need to apply the rules of exponents. Let's break it down step by step:
Step 1: Simplify the coefficients
The coefficient in front of the expression is 6.
Step 2: Multiplying variables with the same base
Let's simplify the variables with the same base, starting with the variable 'a'. We have a^(-5) multiplied by a.
To multiply variables with the same base raised to different powers, we add the exponents. In this case, a^(-5) multiplied by a is equal to a^(-5+1) which simplifies to a^(-4).
So far, our expression becomes:
6a^(-4)b^(2)c^(-3)
Step 3: Simplify 'b' and 'c'
Since b^2 and c^(-3) have different bases, we cannot simplify them any further. Hence, our expression will remain the same:
6a^(-4)b^(2)c^(-3)
That is the simplified form of the given expression.