Algebra
posted by A.W. .
How do I solve for the elimination method: 5x + 3y= 7 and 7x  2y =13 (step 1); 10x + 6y =14 and 21x 6y = 39 ( step 2), 31x/31= 25/31, x= 25/31 (step 4). But after that I get lost. Can somebody help me out please.

Algebra 
Damon
10 x + 6 y = 14 yes
21 x  6 y = 39 yes
add those two
31 x + 0 = 25
so
x = 25/31 yes
Now go back and use 25/31 in either of the original equations to get y
5 (25/31) + 3 y = 7
3 y = 125/31 7
3 y = (125217)/31
y =  92/3
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