what is the volume of a 2.00 gram sample of helium gas at STP?

To determine the volume of a 2.00 gram sample of helium gas at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation and the molar mass of helium.

The ideal gas law equation is: PV = nRT

Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature

At STP, the temperature (T) is 273.15 Kelvin and the pressure (P) is 1 atmosphere (ATM). The molar mass of helium (He) is 4.00 grams per mole (g/mol), which means that 1 mole of helium has a mass of 4.00 grams.

To find the number of moles (n) of helium gas in the sample, we divide the mass by the molar mass:

n = mass / molar mass
n = 2.00 g / 4.00 g/mol
n = 0.50 mol

Now, we can rearrange the ideal gas law equation to solve for volume (V):

V = nRT / P

Let's substitute the values into the equation:
V = (0.50 mol) * (0.0821 L*atm/mol*K) * (273.15 K) / (1 atm)

By calculating this equation, we find that the volume of the 2.00 gram sample of helium gas at STP is approximately 11.2 liters.

To find the volume of a 2.00 gram sample of helium gas at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K). The molar mass of helium (He) is 4.003 grams per mole.

First, we need to find the number of moles of helium gas. We can do this by dividing the mass of the sample by the molar mass:
n = mass / molar mass
n = 2.00 g / 4.003 g/mol
n ≈ 0.4994 mol

Now that we know the number of moles, we can find the volume using the ideal gas law equation. Rearranging the equation to solve for volume:

V = (nRT) / P

Substituting the values into the equation:
V = (0.4994 mol)(0.0821 L·atm / K·mol)(273.15 K) / 1 atm
V ≈ 10.3 L

Therefore, the volume of a 2.00 gram sample of helium gas at STP is approximately 10.3 liters.

1 mole (about 4 grams but you need to confirm the exact mass from the periodic table) occupies 22.4 L. Therefore, 2.0 grams will occupy ?? L.