math b
posted by jojo .
solve each system of equation algebraically:
x2+y2=18
x+y=4

math b 
Damon
Do you mean the circle
x^2+y^2 = 18 ? 
math b 
jojo
yes

math b 
Damon
Making that assumption, we are looking for where the straight line:
y = 1x + 4
which has a slope of 1 and goes through (0,4) and (4,0)
hits the circle with center at the origin and radius 3 sqrt 2 which is about 4.24
Sketch a graph so we will get an idea of how the solution should look.
So
substitute y = x + 4 into the circle
x^2 + (x+4)^2 = 18
x^2 + x^2  8 x + 16 = 18
2 x^2 8 x 2 = 0
x^2  4 x 1 = 0
x = (1/2)[ 4 +/ sqrt (16 +4)]
x = (1/2) [ 4 +/ 2 sqrt 5]
x = 2 +/ sqrt 5
find the y for each of those x values
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